Can I replace a Sky generic router with an Archer A7 AC1750?
Hi guys. This will have been a much discussed topic I would guess but I can't find the advice I need in searching here or elsewhere. I'd appreciate some basic info.
I am on Sky Broadband on FTTP and using their supplied router. It is appalling. I run a home network which is used for a lot of work projects and includes things like 3 PCs, 2 NAS drives, a network print server, home entertainment devices like Freesat box, Chromecast and Sky Puck (that's a one letter misspelling in my estimation), and other itinerant wireless mobile devices. So I have a requirement for fixed IP addresses for many of those items. The router handles this appallingly in my estimation. It spontaneously reboots. I am constantly losing blocks of my fixed IP address settings for no apparent reason. Every time I reset just one the router requires a restart, that is for each one individually and if i have to redefine the whole block it mean over an hour of work. For each reboot it takes an absolute age, much longer than any other router I have ever had.
I would really like to replace this router with my humble Archer A7 AC1750 which was easy to set up and reliable as a Swiss clock made in Japan. I know this is possible as others report it having been done successfully but there seem to be 2 potential ways of doing it to me.
Firstly, I think I could replace the router completely and try logging in to Sky via the Archer. I have and use Wireshark so have gleaned my login credentials for Sky. I do not know if the AC1750 is a model which will allow that degree of takeover. For example, I'm not sure if it offers connection via MER VDSL and can't check that with it now being offline.
Secondly, I'm unsure if I could simply install the AC1750 as just another device on the network inboard of the Sky router and tell the Sky router to stop managing DHCP and turn its WiFi off. Telling the AC1750 to then handle Wifi and DHCP might be enough to do the job.
Can anyone clarify this situation or point me to where I can find the answer? Thanks ahead of your responses.